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Analog electronics circuits miscellaneous

Analog Electronic Circuits

  1. The cutin voltage for each diode shown below Vγ = 0.6 V. Each diode current is 0.5


    1. 10 kΩ, 5 kΩ, 2.93 kΩ
    2. 6 kΩ, 3 kΩ, 3.43 kΩ
    3. 5 kΩ, 6 kΩ, 4.933 kΩ
    4. 6 kΩ, 8 kΩ, 6.43 kΩ
Correct Option: A

From figure
VA = 5 – 0.6 = 4.4 V
VB = 0 – 0.6 = – 0.6 V

R1 =
10 – 0.6 – 4.4
= 10 kΩ
0.5 × 10–3

R2 =
VA – VB
=
4·4 – (0·6)
= 5 kΩ
1 × 10–31 × 10–3

R3 =
VB – (–5)
=
–0.6 + 5
=
4.6
= 2.93 kΩ
1.5 × 10–31.5 × 10–31.5 × 10–3



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