In the circuit of fig. below Zener voltage is Vz = 5 V and

In the circuit of fig. below Zener voltage is V_z = 5 V and β = 100. The value of I_CQ and V_CEQ are:

From figure applying KVL
12 – 500 (I_c + I_b) – V_z – V_BE = 0
12 = 500 I_E + 5 + 0.7
or I_E = I2.6 mA

or I_C = I_E – I_B = I_E –	I_C
	β

or I_C =	β	· I_E =	100	(12.6) mA
	1 + β		1 + 100

= 12.47 mA = I_CQ
V_CE = 12 – 500. (I_E) = 12 – 500 × 12.6 × 10–3 = 5.7
V = V_CEQ
Hence alternative (B) is the correct choice.