Direction: Consider the circuit shown below:
The both transistor have parameter as follows:
VTN = 0.8 V, kn = 30 ΩA/V2
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If the ratio is W = 40 and W = 15, then V0 is: L 1 L 2
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- 2.91 V
- 2.09 V
- 3.41 V
- 1.59 V
Correct Option: A
According to question
= 40 and | = 15 | ||||||||
L | 1 | L | 2 |
Again
Kn1 (VGS1 – VTN1 )2=Kn2 (VGS2 – VTN2 )2
40 (VGS1 – 0.8)2 = 15 (VGS2 – 0.8)2 `…(A)
VGS1 + VGS2 = 5 …(B)
from (A) and (B)
40 (VGS1 – 0.8)2 = 15 (5 – VGS1 – 0.8)2
8 [V2GS1 +.64 –1.6 VGS1] = 3 [17.64 + V2GS1 –8 VGS1]
5 V2GS1 + 11.2 VGS1 – 47.8 = 0
VGS1 = 2.09
V0 = 5 – VGS1
= 5 – 2.09 = 2.91 V