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An amplifier has an open-loop gain of 100, and its lower and upper-cut -off frequency of 100 Hz and 100 kHz, respectively. A feedback network with a feedback factor of 0.99 is connected to the amplifier. The new lower and upper-cut-off frequencies are at___and ___
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- fH = 10 MHz, fL = 1 Hz
- fH = 25 MHz, fL = 10 Hz
- fH = 100 MHz, fL = 100 Hz
- fH =10 MHz, fL = 10 Hz
Correct Option: A
| Af = | = | = 1 | ||
| 1 + Aβ | 1 + 100 × 0·99 |
f*H = fH. (1 + Aβ) = 100 × 103 (1 + 0.99 × 100)
= 10 MHz
| f*L = | = | = 1 = 1 Hz. | ||
| 1 + Aβ | (1 + 100 × 0·99) |
