Assume that the op-amp shown below is ideal. The current

Assume that the op-amp shown below is ideal. The current I through the 1 kΩ resistor is:

Due to virtual ground voltage at terminal A is 0 V. KCL at node A

2 =	V_A – V_B
	2

2 =	0 – V_B
	2

or V_B = – 4 V
Again KCL at B

I =	V_B – V_A	+	V_B – 0
	2		2

or I =	(–4 – 0)	+	–4
	2		2

or I = – 2 – 2 I = – 4 mA
Hence alternative (A) is the correct choice.