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For the circuit shown below gain is Aν = ν0/νi = – 10. The value of R is:
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- 600 kΩ
- 450 kΩ
- 4.5 MΩ
- 6 MΩ
Correct Option: B
Given
| = – 10 | |
| Vi |
KCL at node A
| + | = 0 ...........(1) | ||
| 100 | R |
KCL at node B
| + | + | = 0 ...........(2) | |||
| R | 100 | 100 |
on manipulating
VA = 0. (due to virtual ground)
V0 = – 10 Vi
in equation (1) and (2) we get
| + | = 0 | |||
| 100 | R |
| or Vi = – VB. | .............(3) | |
| R |
| + | + | = | |||||
| R | 100 | 100 | 100 |
| or VB | ![]() | + | + | ![]() | = | ||||
| R | 100 | 100 | 100 |
| or VB | ![]() | + | ![]() | = | · | ![]() | –VB | ![]() | ||||
| R | 100 | 100 | R |
| or | + | = | ||||
| R | 100 | R |
| or | – | = | ||||
| R | R | 100 |
| or | = | |||
| R2 | 100 |
| or | = | |||
| R | 100 |
or R = 450 kΩ

