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Three identical single tuned amplifiers are connected in cascade. The 3 dB bandwidth of each amplifier is 100 kHz. The overall 3 dB bandwidth will be approximately:
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- 300 kHz
- 100 kHz
- 50 kHz
- 33 kHz
Correct Option: C
Given n = 3
fH = 100 kHz
fH* = 3 dB
bandwidth of 3-cascaded stage and is given by the relation
fH* = fH √22 – 1 kHz
= 100 √23 – 1 kHz
= 100 √1.2570 – 1 kHz
≈ 100 × .5 kHz
≈ 50 kHz