For the op-amp shown in fig below open loop differential

For the op-amp shown in fig below open loop differential gain is A_od = 10³. The output voltage ν₀ for ν_i = 2 V is:

KCL at node A.
I₁ = I₀

I₁ =	V_i – V_A
	100 kΩ

I₀ =	V_A – V₀
	100 kΩ

given, A_od = 10³ = –	V₀	and V_i = 2 V
	V_A

or V_A =	–V₀
	10³

Now V_i – V_A = V_A – V_o
or V_i + V_o = 2 V_A

or V_i + V_o = 2 ·		–V₀
		10³

or 2 + V_o =	–2V₀
	10³

or V_o +	2V₀	= – 2
	10³

or V_o =	–2 × 10³	= – 1.996 V
	(10³ + 2)

Hence alternative (A) is the correct choice