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An op-amp has an open-loop gain of 105 and an openloop upper cut off frequency of 10 Hz. If this op-amp is connected as an amplifier with a closed-loop gain of 100. Then the new upper cut off frequency is:
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- 10 Hz
- 100 Hz
- 10 kHz
- 100 kHz
Correct Option: C
Given that
AOL = 105
fH = 10 Hz
ACL = 100
ACL = | ||
1 + AOL · β |
1 + AOL β = | = 103 | |
100 |
Since due to close loop, gain reduces while uppercut off frequency increases by a factor of (1 + AOL β)
fH* = fH (1 + AOL β)
= 10 (103)
= 10 kHz
Hence alternative (C) is the correct choice.