Each transistor in the darlington pair shown below has hFE

Each transistor in the darlington pair shown below has h_FE = 100. The overall h_FE of the composite transistor neglecting leakage current is:

The overall h′_FE of the final stage is given by relation = 100² + 2 × 100 = 10000 + 200 = 10200
(h′_FE = h²_FE + 2 h_FE)