Given X(jω) =jω + 3then x(t)—(jω + 1)2

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Given X(jω) = jω + 3 then x(t)—
(jω + 1)²

1. e^{– t} (1 + 2t) u(t)
2. e^{– t} [1 + 2δ(t)] u(t)
3. e^{– t} (1 + cos ωt + sin ωt) u(t)
4. None of these

Correct Option: A

Given

X(jω) =	jω + 3
	(jω + 1)²

=	1	+	2
	1 + jω		(1 + jω)²

then
x(t) = (e^–t + 2te^–t) u(t)