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Signal and systems miscellaneous
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Signal and systems miscellaneous
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Signals and Systems
Signal and systems miscellaneous
The DTFT of the given signal x[n]=2δ[n – 2]
e
– j2Ω
e
j2Ω
1
None of these
Correct Option:
A
∞
X(e
jΩ
) =
x[n].e
–jΩn
n = – ∞
= e
–2jΩ
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