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Reverse saturation of silicon diode at 25ºC is 20 nA. The reverse saturation current at 60C will be—
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- 20 × 4.5 nA
- 20 × e4.5 nA
- 20 × 2–4.5 nA
- None of these
Correct Option: D
| I’ = I 02 |  | Tf - Ti |  |
| 10 |
| = 20 nA × 2 | | 60° – 25° | |
| 10 |
= 20 × 28.5 nA
Where,
I0 = Leakage current
If = Final temperature
Ii = Initial temperature
