If α = 0·98, ICO = 6 µA and IB = 100 µA for a transistor,

If α = 0·98, I_CO = 6 µA and IB = 100 µA for a transistor, then the value of I_C will be—

Given, I_CO = 6 µA, α = 0·98, I_B = 100 µA, I_C =?
We know that, I_C = βI_B + (1 + β) I_CO

or I_C =		α		I_B +		1 +	α		I_CO
		1 – α					1 – α

or I_C =		0.98		I_B +		1 +	0.98		6 µA
		1 - 0.98					1 – 0.98

or I_C = 49 × 100 µA + 50 × 6 µA
or I_C = 4900 + 300 = 5200 µA = 5·2 mA
Hence alternative (D) is the correct choice.