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Two perfectly matched silicon transistors are connected as shown in figure below. Assuming the β of the transistor to be very high and forward voltage drop in diodes to be 0·7 V, the value of current I is—
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- 0 mA
- 3·6 mA
- 4·3 mA
- 5·7 mA
Correct Option: B
The given circuit
Given, β of a transistor is very high it means IB1 = IB2 ≈ 0,
VBE = 0·7 V. The given circuit can be redrawn as shown below—
From figure— – I × 1 kΩ – 0·7 – 0·7 + 5 = 0
or I = | 1 kΩ |
or I = 3·6 mA
Hence alternative (B) is the correct choice.