For the series connected JFETs, IDSS = 8 mA and VPO =

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For the series connected JFETs, I_DSS = 8 mA and V_PO = – 4V. If V_DD = 15V, R_D = 5 kΩ, R_S = 2 kΩ and R_G = 1 MΩ, find V_DSQ.

1. – 1·22 V
2. – 2·44 V
3. 0 V
4. + 2·44 V

Correct Option: C

The given figure

From above circuit arrangement, we observed that V_GSQ₂ = V_GSQ₁ – V_DSQ₁
But I_DQ1 = I_DQ2
Since V_GSQ₁ = V_GSQ_{2_{therefore V_DSQ₁ = 0V Hence alternative (C) is the correct choice.}}