A junction transistor with β = 49 and ICO = ICBO = 1 µA has IB = 10 µA. The value of IC is given in µA by—
441
490
539
540
Correct Option: D
We know that the collector current is given by the relation IC = βIB + (1 + β) ICO = 49 × 10. 10– 6 + (1 + 49) 1 × 10– 6 = (490 + 50) × 10– 6 = 540 µA.