A CE amplifier has RL = 10 k ohms. Given hie = 1 k ohm,

A CE amplifier has R_L = 10 k ohms. Given h_ie = 1 k ohm, h_fe = 50, h_re = 0, 1/h_oe = 40 K. The voltage gain A_V is—

We know that voltage gain in the case of CE amplifier
A_V = A_I. where A_{I_{= Current gain
Z}L = R_{L/_{= 10 kΩ Z_i = input impedance.}}}

A_I = -	h_fe
	1 + h_oeZ_L

or A_I = –		50	=	- 50	= - 40
		10 × 10³ / 40 × 10³		1 + 25

Z_i = h_ie –	h_fe·h_re
	Y_L + h_oe

Where, Y_L =		1	=	1	= 10^{– 4}
		Z_L		10 × 10³

or Z_i = 1 × 10³ –	50 x 0
	10^–4 + 1 / 40 × 10^–3

Z_i = 10³

Now, A_V₌	40 × 10 × 10³	- 400
	10³