In an emitter follwer with RL =10 K, given hfe = 99, hoe

In an emitter follwer with R_L =10 K, given h_fe = 99, h_oe = (1/40) × 10^–3, h_{i e} = 1 K the values of current gain and input resistance are given by—

In the common emitter amplifier, the current gain is given by the relation,

A_I =	–h_fe
	1 + h_oe · R_L

or \| A_I \| =		99	=	99
		1 + (1 / 40) × 10^–3 × 10 × 10³		1 + (10 / 40)

=	99 x 40	= 79.2 ≅ 80
	50

R_i = h_ie + A_I h_reR_L
= 1K + 80 × 1 × 10K
≅ 800 K