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The transistor in the amplifier shown has following parameters: hfe = 100, hi e = 2 k Ω, hre = 0, hoe = 0.05 m mho. C is very large. The output impedance is—
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- 20 k Ω
- 16 k Ω
- 5 k Ω
- 4 k Ω
Correct Option: A
We know the output impedance, of CE configuration in terms of h-parameter is given as
| Y0 = hoe – | , | hie + RS |
where RS = source resistance
| = 0.05 × 10–3 – | 2 × 103 + RS |
= 0.05 × 10–3
| or Z0 = | = | = 20 kΩ | Y0 | 0.05 × 10–3 |
Hence alternative (A) is the correct answer.
