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α cut-off frequency of a bipolar junction transistor increases with the—
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- Increase in base width
- Increase in emitter width
- Increase in the collector width
- Decrease in the base width
Correct Option: A
We know that,
fα = fT = hfe. | …(i) | |
2πRC |
where, fα = cut-off frequency of a BJT.
hfe = Gain factor
Capacitance C is given as
C = | …(ii) | |
d |
Where
∈0 = free space permittivity
C = capacitance.
A = Area
d = deplection width
from the relation (ii) it is clear that with increase in base width C decreases which increases the fα i.e. α-cut off frequency.
Hence alternative (A) is the correct answer.