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The voltages at V1 and V2 of the arrangement shown in the figure will be respectively—
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- 6 V and 5.4 V
- 5.4 V and 6 V
- 3 V and 5.4 V
- 6 V and 3 V
Correct Option: A
Since for the diode D2 cathode is at higher potential than anode. Hence diode D2 will not conduct, i.e. no current in upper RΩ resistance so V1 = 6 V.
But anode of diode D1 is at higher potential than cathode so the diode D1 will conduct.
V2 = 6 – VT = 6 – .6 = 5.4 V (VT = cut-in voltage of diode)
Hence alternative (A) is the correct answer.