The numbers x, y, z are such that xy = 96050 and xz = 95625

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The numbers x, y, z are such that xy = 96050 and xz = 95625 and y is greater than z by one. Find out the number z ?

1. 425
2. 220
3. 525
4. 225

Correct Option: D

xy = 96050 ...(i)
and xz = 95625 ...(ii)
and y - z = 1 ... (iii)

Dividing (i) by (ii) we get
y/z = 96050 / 95625
= 3842 / 3825
= 226 / 225 ... (iv)

Combining (iii) and (iv) we get z = 225.