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The ages of Harsh and Sumit are 40 yr and 60 yr, respectively. How many year before the ratio of their ages was 3 : 5 ?
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- 15 yr
- 20 yr
- 37 yr
- 10 yr
Correct Option: D
Let k yr before, the ratio of their ages was 3 : 5.
According to the question
(40 - k)/(60 - k) = 3/5
⇒ 200 - 5k = 180 - 3k
⇒ 2k = 20
∴ k = 10
