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Four boys and three girl stand in queue for an interview. The probability that they stand in alternate position is
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- 1/34
- 1/35
- 1/17
- 1/68
- None of the above
Correct Option: B
Total number of possible arrangement for 4 boy and 3 girls in a queue = 7!
when they occupy alternate position then the arrangement would be like
BGBGBGB. Thus the total number of possible arrangement = 4! x 3!
∴ Required probability = 4! x 3! / 7!
= (4 x 3 x 2 x 3 x 2) / (7 x 6 x 5 x 4 x 3 x 2) = 1/35
