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The sum of HCF and LCM of two numbers is 403 and their LCM is 12 times their HCF. If one number is 93, then find the another number.
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- 115
- 122
- 124
- 138
- None of the above
Correct Option: C
Let LCM = m, HCF = n,
According to the question,
m = 12n, .......(i)
and m + n = 403.......(ii)
⇒ 12n + n = 403 [from Eq.(i)]
⇒ 13n = 403
∴ n = 403/13 = 31
∴ m = 12 x 31 = 372
Let the another number = k
∴ 93 x k = 372 x 31
[as product of two numbers HCF x LCM]
⇒ k = (372 x 31)/93 = 124
