Direction: Kolkata Premier League has 16 players seeded from 1 to 16. These players are divided in 4 groups namely South Kolkata, North Kolkata, Central Kolkata and Saltlake. 16 players are divided in these groups as follows :-
South Kolkata : 1, 8, 9, 16
North Kolkata : 2, 7, 10, 15
Central Kolkata : 3, 6, 11, 14
Saltlake : 4, 5, 12,13
In stage I :, each player in a group plays with all the other members in their group exactly once. 2 from each group is selected for stage II based on their number of points. A player qualifying for stage II carries forward only those points that he gained stage I against the another player who qualifies for stage II.
In stage II :, total 8 players (2 from each group) advanced to stage II, where each player plays every other player except the player from same group. At the end of stage II, the top 4 players on the basis of points would qualify for the IIIrd stage the Semi-Final stage.
Stage III : (Semi-Final), winners of the Semi-Final advanced to the final round and losers play for 3rd place. The following more rules of tournament is as follows :
(i) Points in stage I and stage II are awarded as follows : winner 2 points, looser 0 points.
(ii) An ‘upset’ is caused when, in any match a lower seeded player beats a higher seeded player.
(iii) There is no ties at any stage.
(iv) If points of the two players at the end of any stage are same then there is a complex rule to calculate the tie breaker.
(v) Seed 1 is the highest seed and seed 16 is the lowest rank seed.
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If Ricky Singh a lucky player from South Kolkata reached semi final stage after getting the minimum possible points, then what is the point scored by Mr. Ricky Singh.
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- 4
- 5
- 7
- None of these
Correct Option: A
In stage I, in a group in total 6 matches and that will have 12 points in total.
Total number of matches in this stage is 4 × 6 = 24
In stage II, total 8 players and they play each other except a player who comes from same group but point of their match in stage I is carried forward hence in stage II total points is 28 × 2 = 56.
Number of matches in stage II is 7 × ( 8/2 ) – 4 = 24
In this case we have to minimize the points scored by 4th ranker (Who advanced to Semi Final). In order to minimize the points scored by Ricky Singh top three players should get maximum points, Let points achieved by top three player at the end of stage II is 14, 12 and 10 summing up to 14 + 12 + 10 = 36 and remaining points 56 - 36 = 20 got distributed to bottom 5 players.
To minimize the points scored by Ricky Singh, all of the bottom five got same point (20/5 = 4 points) and with complex tie breaker Ricky is advanced to Semifinal.
