Ⅰ. 2x2 + 11x + 14 = 0 Ⅱ. 4y2 + 12y + 9 = 0

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Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
( 1 ) if x > y
( 2 ) if x ≥ y
( 3 ) if x < y
( 4 ) if x ≤ y
( 5 ) if x = y or the relationship cannot be established.

Ⅰ. 2x² + 11x + 14 = 0
Ⅱ. 4y² + 12y + 9 = 0

1. 1
2. 2
3. 3
4. 4
5. 5

Correct Option: C

From the given equations , we have
Ⅰ. 2x² + 11x + 14 = 0
⇒ 2x² + 7x + 4x + 14 = 0
⇒ x( 2x + 7 ) + 2( 2x + 7 ) = 0
⇒ ( x + 2 )( 2x + 7 ) = 0

⇒ x =	-7	or -2
	2

Ⅱ. 4y² + 12y + 9 = 0
⇒ ( 2y + 3 )² = 0
⇒ ( 2y + 3 )( 2y + 3 ) = 0

⇒ y =	-3	,	-3
	2		2

From above both equations it is clear that x < y is correct answer .