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Direction: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
( 1 ) x > y
( 2 ) x ≥ y
( 3 ) x < y
( 4 ) x ≤ y
( 5 ) x = y or the relationship cannot be established.

Ⅰ. x² – 11x + 24 = 0
Ⅱ. 2y² – 9y + 9 = 0

1. 1
2. 2
3. 3
4. 4
5. 5

Correct Option: B

According to question ,we can say that
From equation Ⅰ. x² – 11x + 24 = 0
⇒ x² – 8x – 3x + 24 = 0
⇒ x(x – 8) – 3(x – 8) = 0
⇒ (x – 3)(x – 8) = 0
There4; x = 3 or, 8
From equation Ⅱ. 2y² – 9y + 9 = 0
⇒ 2y² – 3y – 6y + 9 = 0
⇒ y(2y – 3) – 3(2y – 3) = 0
⇒ (2y – 3)(y – 3) = 0

∴ y =	3	or, 3
	2

∴ x ≥ y
From above equations it is clear that x ≥ y is correct answer .