Ⅰ. 2x2 + 3x – 20 = 0 Ⅱ. 2y2 + 19y + 44 =

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Direction: In each of these questions, two equations Ⅰ and Ⅱ are given. You have to solve both the equations and give answer
( 1 ) if x < y
( 2 ) if x > y
( 3 ) if x = y
( 4 ) if x ≥ y
( 5 ) if x ≤ y or no relationship can be established between x and y.

Ⅰ. 2x² + 3x – 20 = 0
Ⅱ. 2y² + 19y + 44 = 0

1. 1
2. 2
3. 3
4. 4
5. 5

Correct Option: D

According to question ,
From equation Ⅰ. 2x² + 3x– 20 = 0
⇒ 2x² + 8x − 5x − 20 = 0
⇒ 2x(x + 4) − 5(x + 4) = 0
⇒ (2x − 5)(x + 4) = 0

∴ x =	5	, - 4
	2

From equation Ⅱ. 2y² + 19y + 44 = 0
⇒ 2y² + 11y + 8y + 44 = 0
⇒ 2y(2y + 11) + 4(2y + 11) = 0
⇒ (y + 4)(2y + 11) = 0

∴ y = - 4, -	5
	2

Hence, x ≥ y is correct answer .