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Consider the equation px2 + qx + r = 0, where p, q, r are real. The roots are equal in magnitude but opposite in sign when :
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- q = 0, r = 0, p ≠ 0
- p = 0, qr ≠ 0
- r = 0, pr ≠ 0
- q = 0, pr ≠ 0
- q = 0, r = 0, p ≠ 0
Correct Option: D
As per the given above question , we can say that
Let, the roots be α and −α. Then, sum of roots = 0 Also, roots being not equal, discriminant ≠ 0
| ∴ | = 0 and q2 - 4pr ≠ 0 | |
