Direction: Study the following information carefully to answer the question the question that follow.
A box contains 2 blue caps, 4 red caps, 5 green caps and 1 yellow cap.
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If four caps are picked at random, what is the probability that none is green ?
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- 7/99
- 5/99
- 7/12
- 5/12
Correct Option: A
Total number of caps = 12
Total number of result = n(S) = 12C4 = 495
Out of 5 caps, number of ways to not pick a green cap = n(E1) = 5C0 = 1
and out of 7 caps, number of ways to pic 4 caps = n(E) = 7C4 = 35
∴ Required probability = (1 x 35)/495 = 7/99
