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A person distributes his pens among four friends A, B, C and D in the ratio 1/3 : 1 / 4 : 1/5 : 1/6. What is the minimum number of pens that the person should have ?
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- 75
- 45
- 57
- 65
Correct Option: C
The ratio among A, B, C and D = 1/3 : 1 / 4 : 1/5 : 1/6
On rearranging the ratio = 60/3 : 60/4: 60/5 : 60/6 = 20 : 15 : 12 : 10
So minimum number of pens can be when the common ration is 1.
So minimum number of pen = 20 + 15 + 12 + 10 = 57
