Let a/3 = b/8 = K Then, a = 3K, b = 8K∴ (a + 3) / (b + 8) = (3K + 3) / (8K + 8) = [3( K + 1)] / [8(K+1)] = 3/8 ∴ ( a + 3 ) : (b + 8) = 3 : 8
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