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A walks 10 meters in front and 10 meters to the right. Then every time turning to his left, he walks 5, 15 and 15 meters respectively. How far is he now from his starting point?
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- 5 meters
- 10 meters
- 20 meters
- 23 meters
- None of these
- 5 meters
Correct Option: A
The movements of A are as shown in Figure (O to P, P to Q, Q to R, R to S and S to T)
Since TS = OP + QR, so T lies in line with O. A’s distance from the starting point O = OT = (RS – PQ) = (15 – 10)m = 5 m.