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in a mixture of 60 L the ratio of acid and water is 2 : 1. If the ratio of acid and water is to be 1 : 2, then the amount of water (in liters) to be added to the mixture is ?
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- 55
- 60
- 50
- 45
Correct Option: B
Quantity of acid in the mixture = (2/3) x 60 = 40 L
Quantity of water in the mixture = (1/3) x 60= 20 L
Let the required quantity of water be x L.
According to the question,
40/(20+ x) = 1/2
⇒ 80 = 20 + x
⇒ x = 60 L
