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A person gave 2/5 part of his income to his elder son and 30 % part to his younger son. He saved his remaining money in three trusts. A, B and C in the ratio of 3 : 5 : 2. If difference between the amount got by his both sons is &8377; 2000, How much amount he saved in trust C ?
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- ₹ 1000
- ₹ 1140
- ₹ 1200
- ₹ 1256
Correct Option: C
Let the person have ₹ N
Then shares of elder don = ₹ 2N/5
and share of younger son = ₹ 3N/10
According to the question,
2N/5 - 3N/10 = 2000
⇒ N/10 = 2000
⇒ N = 20000
Remaining amount saved in trusts
= 1 - (2N/5 + 3N/10 ) = 1 - (4N + 3N)/10
= 1 - 7N/10 = 3N/10 x 20000 = 6000
given that A : B : C = 3 : 5: 2
∴ Share of C = [2/(3 + 5 +2)] x 6000
= (2/10) x 6000 = ₹ 1200
