A train running at 8/11 of its own speed reached a place

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A train running at 8/11 of its own speed reached a place in 5¹/₂ h. How much time could be saved, if the train would have run as its own speed ?

1. 2¹/₂ h
2. 2 h
3. 1¹/₂ h
4. 1 h

Correct Option: C

New speed = 8/11 of usual speed
New time = 11/8 of usual time
∴ 11/8 of usual time = 11/2 h
⇒ Usual time = (11 x 8)/(2 x 11) = 4 h
∴ Time saved = 5¹/₂- 4
= 1¹/₂