(4/√x) + (7/√x) = √x; y2

Home » Aptitude » Quadratic Equation » Question

Direction: In each of the following question, there are two equations. you have to solve both equations and give answer.

(4/√x) + (7/√x) = √x;
y² - (11)^5/2/√y = 0

1. if x > y
2. if x ≥ y
3. if x < y
4. if x ≤ y
5. If x = y or relation cannot be established

Correct Option: E

4/√x + 7/√x = √x;
⇒ 11/√x = √x
∴ x = 11
and y² - (11)^5/2/√y = 0
⇒ y² = (11)^5/2/(y)^1/2
⇒ y² x y^1/2 = (11)^5/2
⇒ (y)^5/2 = (11)^5/2
∴ y = 11
∴ x = y