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If a and b are the roots of the equation x2 - 6x + 6 = 0, find the value of 2(a2 + b2).
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- 40
- 42
- 48
- 46
- None of the above
Correct Option: C
a and b are the roots of the equation
x2 - 6x + 6 = 0
∴ a + b = -B/A = 6 and ab = C/A = 6
We know that,
a2 + b2 = (a + b)2 - 2ab
= (6)2 - 2 x 6 = 36 - 12 = 24
∴ 2(a2 + b2) = 2 x 24 = 48