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Two numbers are less than a third number by 30%and 37% respectively. How much percent is the second number less than the first ?
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- 3%
- 4%
- 7%
- 10%
Correct Option: D
Let third number be N
Then, first number = 70% of N = 7N/10 and,
Second number = 63% of N = 63N/100
Difference = 7N/10 - 63N/100 = 7N/100
∴ Required percentage = (7N/100) x (10/7N) x 100 % = 10%
